What is the solution for (dx)/(dt)=-3x(x^2-1) ?

The solution for (dx)/(dt)=-3x(x^2-1) is x=sqrt(1/(-e^{-6t-c_{1))+1}},x=-sqrt(1/(-e^{-6t-c_{1))+1}}

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(dx)/(dt)=-3x(x^2-1)

\frac{d x}{d t} = - 3 x (x^{2} - 1)

x = \frac{1}{- e ^{- 6 t - c_{1}} + 1}, x = - \frac{1}{- e ^{- 6 t - c_{1}} + 1}

Solution steps

\frac{d x}{d t} = - 3 x (x^{2} - 1)

Solve Bernoulli ODE:

x = \frac{1}{- e ^{- 6 t - c_{1}} + 1}, x = - \frac{1}{- e ^{- 6 t - c_{1}} + 1}

x = \frac{1}{- e ^{- 6 t - c_{1}} + 1}, x = - \frac{1}{- e ^{- 6 t - c_{1}} + 1}

\int \frac{sin ( \frac{π}{x} )}{x ^{2}} d x

\frac{d y}{d t} = \frac{t ^{2}}{y ( 2 + t ^{3} )}

\frac{d}{d x} (sin (\frac{π}{2}))

x \to 0 lim (\frac{e ^{x} - 1}{x ^{3}})

\frac{3 x + 2}{3 x - 2}

What is the solution for (dx)/(dt)=-3x(x^2-1) ?
The solution for (dx)/(dt)=-3x(x^2-1) is x=sqrt(1/(-e^{-6t-c_{1))+1}},x=-sqrt(1/(-e^{-6t-c_{1))+1}}