What is the derivative of y=e^{-mx} ?

The derivative of y=e^{-mx} is -me^{-mx}

What is the first derivative of y=e^{-mx} ?

The first derivative of y=e^{-mx} is -me^{-mx}

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derivative of

y = e^{- m x}

- m e^{- m x}

Solution steps

\frac{d}{d x} (e^{- m x})

Apply the chain rule:

e^{- m x} \frac{d}{d x} (- m x)

= e^{- m x} \frac{d}{d x} (- m x)

\frac{d}{d x} (- m x) = - m

= e^{- m x} (- m)

Simplify

= - m e^{- m x}

3 sin (2 x)

\int \frac{x}{x + 2} d x

x y^{^{''}} + 2 y^{^{'}} = 6 x

\frac{d}{d y} (\frac{y}{x ^{2} + y ^{2} + z ^{2}})

\int \frac{sin ( x )}{cos ^{2} ( x )} d x

What is the derivative of y=e^{-mx} ?
The derivative of y=e^{-mx} is -me^{-mx}
What is the first derivative of y=e^{-mx} ?
The first derivative of y=e^{-mx} is -me^{-mx}