What is the solution for x*(dy)/(dx)+y=-6xy^2,y(1)=-7 ?

The solution for x*(dy)/(dx)+y=-6xy^2,y(1)=-7 is y= 7/(x(42ln(x)-1))

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x*(dy)/(dx)+y=-6xy^2,y(1)=-7

x \cdot \frac{d y}{d x} + y = - 6 x y^{2}, y (1) = - 7

y = \frac{7}{x ( 42 ln ( x ) - 1 )}

Solution steps

x \cdot \frac{d y}{d x} + y = - 6 x y^{2}

Solve Bernoulli ODE:

y = \frac{7}{x ( 42 ln ( x ) - 1 )}

y = \frac{7}{x ( 42 ln ( x ) - 1 )}

\frac{d}{d x} (e^{(e^{x^{2}})})

\int \frac{e \frac{1}{t} + 2}{t ^{2}} d t

x \to 6 lim (\frac{x}{x ^{2} + 1})

x \to 1 - lim (\frac{1 + x}{1 - x})

f (x) = \frac{x}{1 - ln ( x - 1 )}

What is the solution for x*(dy)/(dx)+y=-6xy^2,y(1)=-7 ?
The solution for x*(dy)/(dx)+y=-6xy^2,y(1)=-7 is y= 7/(x(42ln(x)-1))