What is the integral of 5/((x^2)) ?

The integral of 5/((x^2)) is -5/x+C

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integral of 5/((x^2))

\int \frac{5}{( x ^{2} )} d x

- \frac{5}{x} + C

Solution steps

\int \frac{5}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int \frac{1}{x ^{2}} d x

Apply the Power Rule

: - \frac{1}{x}

= 5 (- \frac{1}{x})

Simplify

5 (- \frac{1}{x}) : - \frac{5}{x}

= - \frac{5}{x}

Add a constant to the solution

= - \frac{5}{x} + C

\int \frac{1}{y - y ^{2}} d y

\frac{\partial}{\partial x} (18 x y e^{- x^{2} - y^{2}})

\frac{\partial}{\partial x} (s t)

x = - 2, x = 3, y = 2 x, y = x^{2} - 3

\frac{\partial}{\partial x} (lo g_{e} (x + y))