What is the tangent of f(x)=sqrt(10x),\at x=10 ?

The tangent of f(x)=sqrt(10x),\at x=10 is y= 1/2 x+5

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tangent of f(x)=sqrt(10x),\at x=10

tangent of

f (x) = 10 x, at x = 10

y = \frac{1}{2} x + 5

Solution steps

Find the tangent point:

(10, 10)

Find the slope of

f (x) = 10 x : \frac{df ( x )}{d x} = \frac{5}{2 x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{2}

Find the line with slope m=

\frac{1}{2}

and passing through

(10, 10) : y = \frac{1}{2} x + 5

y = \frac{1}{2} x + 5

y = - x^{2} + 5 x + 2, y = 2

\frac{d}{d x} (\frac{( x ^{2} + 2 x - 5 )}{( x + 1 ) ^{2}})

y^{^{''}} - 2 y^{^{'}} + 2 y = 0, y (0) = 0, y^{^{'}} (0) = 1

y = arcsin (\frac{1}{x})

\int 5 ln (x^{2} - x + 12) d x

What is the tangent of f(x)=sqrt(10x),\at x=10 ?
The tangent of f(x)=sqrt(10x),\at x=10 is y= 1/2 x+5