What is the derivative of ln(9-x^2) ?

The derivative of ln(9-x^2) is -(2x)/(9-x^2)

What is the first derivative of ln(9-x^2) ?

The first derivative of ln(9-x^2) is -(2x)/(9-x^2)

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\frac{d}{d x} (ln (9 - x^{2}))

- \frac{2 x}{9 - x ^{2}}

Solution steps

\frac{d}{d x} (ln (9 - x^{2}))

Apply the chain rule:

\frac{1}{9 - x ^{2}} \frac{d}{d x} (9 - x^{2})

= \frac{1}{9 - x ^{2}} \frac{d}{d x} (9 - x^{2})

\frac{d}{d x} (9 - x^{2}) = - 2 x

= \frac{1}{9 - x ^{2}} (- 2 x)

Simplify

\frac{1}{9 - x ^{2}} (- 2 x) : - \frac{2 x}{9 - x ^{2}}

= - \frac{2 x}{9 - x ^{2}}

f (x) = (9 x^{9} - 9) (8 - 8 x^{8}), at x = 0

\int - \frac{1}{sin ( x )} d x

\int_{0}^{4} x e^{- a x} d x

e^{8 x}

\int x^{2} 81 - x^{2} d x

What is the derivative of ln(9-x^2) ?
The derivative of ln(9-x^2) is -(2x)/(9-x^2)
What is the first derivative of ln(9-x^2) ?
The first derivative of ln(9-x^2) is -(2x)/(9-x^2)