What is the limit as x approaches 2 of sqrt(2x-4)+8 ?

The limit as x approaches 2 of sqrt(2x-4)+8 is 8

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limit as x approaches 2 of sqrt(2x-4)+8

x \to 2 lim (2 x - 4 + 8)

8

Solution steps

x \to 2 lim (2 x - 4 + 8)

Plug in the value

x = 2

= 2 \cdot 2 - 4 + 8

Simplify

= 8

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\frac{d}{d x} (\frac{8}{3 x ^{2}} + \frac{3}{2 x} + 2)

3 x + 7

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\int 10 x + 11 d x

What is the limit as x approaches 2 of sqrt(2x-4)+8 ?
The limit as x approaches 2 of sqrt(2x-4)+8 is 8