What is the derivative of (5t^2)/2+t+6 ?

The derivative of (5t^2)/2+t+6 is 5t+1

What is the first derivative of (5t^2)/2+t+6 ?

The first derivative of (5t^2)/2+t+6 is 5t+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

\frac{5 t ^{2}}{2} + t + 6

5 t + 1

Solution steps

\frac{d}{d t} (\frac{5 t ^{2}}{2} + t + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (\frac{5 t ^{2}}{2}) + \frac{d t}{d t} + \frac{d}{d t} (6)

\frac{d}{d t} (\frac{5 t ^{2}}{2}) = 5 t

\frac{d t}{d t} = 1

\frac{d}{d t} (6) = 0

= 5 t + 1 + 0

Simplify

= 5 t + 1

\frac{d}{d t} (4 t e^{3 t})

y = x^{2} - 3 x - 5

\int cos (\frac{π}{3} x) d x

\frac{d ^{3}}{d x ^{3}} ((1 + x)^{3})

\int \frac{x}{- 7 - 8 x - x ^{2}} d x

What is the derivative of (5t^2)/2+t+6 ?
The derivative of (5t^2)/2+t+6 is 5t+1
What is the first derivative of (5t^2)/2+t+6 ?
The first derivative of (5t^2)/2+t+6 is 5t+1