What is the solution for 1/(y^{1/3)}dy=1dx ?

The solution for 1/(y^{1/3)}dy=1dx is

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1/(y^{1/3)}dy=1dx

\frac{1}{y ^{\frac{1}{3}}} d y = 1 d x

y = \frac{2 2 x ^{3} + c _{1}^{3} + 3 c _{1} x ^{2} + 3 c _{1}^{2} x}{3 3}, y = - \frac{2 2 x ^{3} + c _{1}^{3} + 3 c _{1} x ^{2} + 3 c _{1}^{2} x}{3 3}

Solution steps

\frac{1}{y ^{\frac{1}{3}}} d y = 1 d x

Solve separable ODE:

y = \frac{2 2 x ^{3} + c _{1}^{3} + 3 c _{1} x ^{2} + 3 c _{1}^{2} x}{3 3}, y = - \frac{2 2 x ^{3} + c _{1}^{3} + 3 c _{1} x ^{2} + 3 c _{1}^{2} x}{3 3}

y = \frac{2 2 x ^{3} + c _{1}^{3} + 3 c _{1} x ^{2} + 3 c _{1}^{2} x}{3 3}, y = - \frac{2 2 x ^{3} + c _{1}^{3} + 3 c _{1} x ^{2} + 3 c _{1}^{2} x}{3 3}

\frac{\partial}{\partial x} (300 e^{x t})

\int - 4 sin (2 x) + 3 cos (3 x) d x

x \to 0 + lim (x sin (\frac{1}{x}))

P (t) = 0.45 t^{2} - 12 t + 105

\frac{d}{d x} ((cos (x)) sin (x))

What is the solution for 1/(y^{1/3)}dy=1dx ?
The solution for 1/(y^{1/3)}dy=1dx is