What is the derivative of 4sec(θ) ?

The derivative of 4sec(θ) is 4sec(θ)tan(θ)

What is the first derivative of 4sec(θ) ?

The first derivative of 4sec(θ) is 4sec(θ)tan(θ)

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derivative of

4 sec (θ)

4 sec (θ) tan (θ)

Solution steps

\frac{d}{d θ} (4 sec (θ))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d θ} (sec (θ))

Apply the common derivative:

\frac{d}{d θ} (sec (θ)) = sec (θ) tan (θ)

= 4 sec (θ) tan (θ)

\frac{\partial}{\partial x} (x^{\frac{3}{2}} y)

\frac{d}{d x} ((5 x + 6)^{2})

f (x) = 4 x, at x = 9

5 \frac{d y}{d x} + 2 x = 3

\int \frac{3 x ^{2} + 1}{x ^{3} + x} d x

What is the derivative of 4sec(θ) ?
The derivative of 4sec(θ) is 4sec(θ)tan(θ)
What is the first derivative of 4sec(θ) ?
The first derivative of 4sec(θ) is 4sec(θ)tan(θ)