What is the integral from 0 to 1 of 1/(x^{-2)} ?

The integral from 0 to 1 of 1/(x^{-2)} is 1/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of 1/(x^{-2)}

\int_{0}^{1} \frac{1}{x ^{- 2}} d x

\frac{1}{3}

Decimal

0.33333 \dots

Solution steps

\int_{0}^{1} \frac{1}{x ^{- 2}} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{1}

= [\frac{x ^{3}}{3}]_{0}^{1}

Compute the boundaries:

\frac{1}{3}

= \frac{1}{3}

\frac{d}{d x} (x^{2} cos (\frac{1}{x}))

t^{^{'}}

\frac{\partial}{\partial x} (\frac{3 x}{4})

\frac{d y}{d x} = k y

f (x) = 4 - 3 x^{2}, (- 2, - 8)

What is the integral from 0 to 1 of 1/(x^{-2)} ?
The integral from 0 to 1 of 1/(x^{-2)} is 1/3