What is derivative of f(x)=\sqrt[4]{t}-4e^t ?

The answer to derivative of f(x)=\sqrt[4]{t}-4e^t is (dt)/(dx)=0

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derivative of f(x)=\sqrt[4]{t}-4e^t

derivative of

f (x) = 4 t - 4 e^{t}

\frac{d t}{d x} = 0

Solution steps

f (x) = 4 t - 4 e^{t}

Treat

t

t (x)

Differentiate both sides:

0 = \frac{\frac{d t}{d x}}{4 t ^{\frac{3}{4}}} - e^{t} \frac{d t}{d x}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

\int sin (21 x) d x

ln (x e^{- 4 x})

\int cos^{10} (x) sin^{3} (x) d x

\frac{\partial}{\partial y} (y^{2} - x^{2})

\int (3 + x)^{2} ln (4 x) d x

What is derivative of f(x)=\sqrt[4]{t}-4e^t ?
The answer to derivative of f(x)=\sqrt[4]{t}-4e^t is (dt)/(dx)=0