What is the derivative of y=3xe^x ?

The derivative of y=3xe^x is 3(e^x+e^xx)

What is the first derivative of y=3xe^x ?

The first derivative of y=3xe^x is 3(e^x+e^xx)

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derivative of

y = 3 x e^{x}

3 (e^{x} + e^{x} x)

Solution steps

\frac{d}{d x} (3 x e^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (x e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{x}

= 3 (\frac{d x}{d x} e^{x} + \frac{d}{d x} (e^{x}) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x}) = e^{x}

= 3 (1 \cdot e^{x} + e^{x} x)

Simplify

= 3 (e^{x} + e^{x} x)

x \to 1 + lim (x^{\frac{3}{1 - x}})

y^{^{'}} + y^{3} = 0

y^{^{''}} + 4 y^{^{'}} + 4 y = (3 + x) e^{- 2 x}

- 4 e^{t}

\int 1 + sin (2 x) d x

What is the derivative of y=3xe^x ?
The derivative of y=3xe^x is 3(e^x+e^xx)
What is the first derivative of y=3xe^x ?
The first derivative of y=3xe^x is 3(e^x+e^xx)