What is the derivative of (x^2+7^3) ?

The derivative of (x^2+7^3) is 6x(x^2+7)^2

What is the first derivative of (x^2+7^3) ?

The first derivative of (x^2+7^3) is 6x(x^2+7)^2

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\frac{d}{d x} ((x^{2} + 7)^{3})

6 x (x^{2} + 7)^{2}

Solution steps

\frac{d}{d x} ((x^{2} + 7)^{3})

Apply the chain rule:

3 (x^{2} + 7)^{2} \frac{d}{d x} (x^{2} + 7)

= 3 (x^{2} + 7)^{2} \frac{d}{d x} (x^{2} + 7)

\frac{d}{d x} (x^{2} + 7) = 2 x

= 3 (x^{2} + 7)^{2} \cdot 2 x

Simplify

= 6 x (x^{2} + 7)^{2}

x \to - 10 lim (3 x - 8)

\frac{\partial}{\partial r} (r sin (x))

\frac{d y}{d x} = 8 x^{7} cos^{2} (y)

f (x) = 8 (x^{3} - x)^{4}

y^{^{''}} + 2 y = 10

What is the derivative of (x^2+7^3) ?
The derivative of (x^2+7^3) is 6x(x^2+7)^2
What is the first derivative of (x^2+7^3) ?
The first derivative of (x^2+7^3) is 6x(x^2+7)^2