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Popular >

y^'=(x^8-2y)/x

Solution

y^{^{'}} = \frac{x ^{8} - 2 y}{x}

Solution

y = \frac{x ^{8}}{10} + \frac{c _{1}}{x ^{2}}

Solution steps

y^{'} (x) = \frac{x ^{8} - 2 y}{x}

Solve linear ODE:

y = \frac{x ^{8}}{10} + \frac{c _{1}}{x ^{2}}

y = \frac{x ^{8}}{10} + \frac{c _{1}}{x ^{2}}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=(x^8-2y)/x ?
The solution for y^'=(x^8-2y)/x is y=(x^8)/(10)+(c_{1})/(x^2)