What is area y=sqrt(x),y=x^2,y=1 ?

The answer to area y=sqrt(x),y=x^2,y=1 is No Solution

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area y=sqrt(x),y=x^2,y=1

area

y = x, y = x^{2}, y = 1

No Solution

Solution steps

To find the intersection points solve

f_{i} (x) = f_{j} (x)

x = x^{2} : x = 0, x = 1

x = 1 : x = 1

x^{2} = 1 : x = 1, x = - 1

Curves not bounded

= No Solution

\int \frac{cos ( \frac{π}{x ^{3}} )}{x ^{4}} d x

lo g_{4} (sec^{2} (5 x^{3} - 4 x^{2}))

\int \frac{2 x - 4 + 3 x}{x} d x

\int_{0}^{30} 500 d x

(y^{3} - 1) e^{x} d x + 3 y^{2} (e^{x} + 1) d y = 0, y (0) = 2

What is area y=sqrt(x),y=x^2,y=1 ?
The answer to area y=sqrt(x),y=x^2,y=1 is No Solution