What is the solution for x(dy)/(dx)=x^3+4x^3y ?

The solution for x(dy)/(dx)=x^3+4x^3y is y=(e^{(4x^3+c_{1})/3})/(4)-1/4

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x(dy)/(dx)=x^3+4x^3y

x \frac{d y}{d x} = x^{3} + 4 x^{3} y

y = \frac{e ^{\frac{4 x ^{3} + c _{1}}{3}}}{4} - \frac{1}{4}

Solution steps

x \frac{d y}{d x} = x^{3} + 4 x^{3} y

Solve separable ODE:

y = \frac{e ^{\frac{4 x ^{3} + c _{1}}{3}}}{4} - \frac{1}{4}

y = \frac{e ^{\frac{4 x ^{3} + c _{1}}{3}}}{4} - \frac{1}{4}

n = 1 \sum \infty \frac{n 5 ^{n}}{n !}

5 tan (x)

x (x - 14)

x \to 0 lim (e^{- x})

\frac{s - 1}{s ( s - 1 ) + 2}

What is the solution for x(dy)/(dx)=x^3+4x^3y ?
The solution for x(dy)/(dx)=x^3+4x^3y is y=(e^{(4x^3+c_{1})/3})/(4)-1/4