What is the integral of 4sin(y) ?

The integral of 4sin(y) is -4cos(y)+C

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integral of 4sin(y)

\int 4 sin (y) d y

- 4 cos (y) + C

Solution steps

\int 4 sin (y) d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int sin (y) d y

Use the common integral:

\int sin (y) d y = - cos (y)

= 4 (- cos (y))

Simplify

= - 4 cos (y)

Add a constant to the solution

= - 4 cos (y) + C

\frac{d}{d x} (e^{- 4 x} sin (3 x))

\frac{d y}{d x} = \frac{1 - x y ^{2}}{2 x ^{2} y}

\frac{\partial}{\partial x} (z (2 x y))

y^{^{'}} + y - 2 = 0

x \to 2 lim (2 x^{2} - 7 x + 4)