What is the limit as x approaches 0 of (1+4x) 1/x ?

The limit as x approaches 0 of (1+4x) 1/x is diverges

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limit as x approaches 0 of (1+4x) 1/x

x \to 0 lim ((1 + 4 x) \frac{1}{x})

diverges

Solution steps

x \to 0 lim ((1 + 4 x) \frac{1}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim ((1 + 4 x) \frac{1}{x}) = \infty

x \to 0 - lim ((1 + 4 x) \frac{1}{x}) = - \infty

= diverges

f (x) = x^{4}, at x = 4

x \to \infty lim (\frac{ln ( x ) + x}{x n x})

f (x) = \frac{3 x ^{2} + 1}{x ^{\frac{3}{2}}}

\int e^{i 8 x} cos (4 x) d x

f (x) = \frac{x ^{2} - 5 x}{x + 1}

What is the limit as x approaches 0 of (1+4x) 1/x ?
The limit as x approaches 0 of (1+4x) 1/x is diverges