What is the sum from k=1 to infinity of (-3/4)^{k-1} ?

The sum from k=1 to infinity of (-3/4)^{k-1} is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from k=1 to infinity of (-3/4)^{k-1}

k = 1 \sum \infty (- \frac{3}{4})^{k - 1}

converges

Solution steps

k = 1 \sum \infty (- \frac{3}{4})^{k - 1}

Apply Series Ratio Test:

converges

= converges

\frac{d}{d x} (\frac{1}{x} - x)

\int cos^{8} (4 - x) sin (4 - x) d x

\int \frac{1}{1 - 2 x ^{2}} d x

f (x) = x^{2} - 2 x, (- 2, 8)

\frac{x ^{2} - 1}{x}

What is the sum from k=1 to infinity of (-3/4)^{k-1} ?
The sum from k=1 to infinity of (-3/4)^{k-1} is converges