What is the limit as x approaches 0 of 6x-ln(6x+1) ?

The limit as x approaches 0 of 6x-ln(6x+1) is 0

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limit as x approaches 0 of 6x-ln(6x+1)

x \to 0 lim (6 x - ln (6 x + 1))

0

Solution steps

x \to 0 lim (6 x - ln (6 x + 1))

Plug in the value

x = 0

= 6 \cdot 0 - ln (6 \cdot 0 + 1)

Simplify

6 \cdot 0 - ln (6 \cdot 0 + 1) : 0

= 0

y^{^{''}} + 16 y = t e^{t} cos (4 t)

\frac{d}{d x} (\frac{2}{x} - x^{2} + 1)

\int x (e^{x^{2}} - 1) d x

y^{^{''}} - 5 y^{^{'}} = 25 t

\int_{3}^{3} \frac{6}{9 + x ^{2}} d x

What is the limit as x approaches 0 of 6x-ln(6x+1) ?
The limit as x approaches 0 of 6x-ln(6x+1) is 0