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Popular >

area 5x-x^2,x,0,4

Solution

area

5 x - x^{2}, x, 0, 4

Solution

\frac{32}{3}

+1

Decimal

10.66666 \dots

Solution steps

Apply the area formula:

\int_{0}^{4} - x^{2} + 4 x d x

Solve

\int_{0}^{4} - x^{2} + 4 x d x : \frac{32}{3}

The area is:

= \frac{32}{3}

Graph

Popular Examples

sum from n=3 to infinity of (5^n)/(14^n)

n = 3 \sum \infty \frac{5 ^{n}}{1 4 ^{n}}

integral of x*e^{4x}

\int x \cdot e^{4 x} d x

area x=4y^3,x=22y^2 area

x = 4 y^{3}, x = 22 y^{2}

derivative of 4x-x^3

\frac{d}{d x} (4 x - x^{3})

integral of (x^2+2x)/(x^3+3x^2-5)

\int \frac{x ^{2} + 2 x}{x ^{3} + 3 x ^{2} - 5} d x

Frequently Asked Questions (FAQ)

What is area 5x-x^2,x,0,4 ?
The answer to area 5x-x^2,x,0,4 is 32/3