What is the tangent of y= 1/(x^3),(-3,-1/27) ?

The tangent of y= 1/(x^3),(-3,-1/27) is y=-1/27 x-4/27

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tangent of y= 1/(x^3),(-3,-1/27)

tangent of

y = \frac{1}{x ^{3}}, (- 3, - \frac{1}{27})

y = - \frac{1}{27} x - \frac{4}{27}

Solution steps

Find the slope of

y = \frac{1}{x ^{3}} : \frac{d y}{d x} = - \frac{3}{x ^{4}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{27}

Find the line with slope m=

- \frac{1}{27}

and passing through

(- 3, - \frac{1}{27}) : y = - \frac{1}{27} x - \frac{4}{27}

y = - \frac{1}{27} x - \frac{4}{27}

\frac{d}{d x} (6 x - 7)

x^{2} y^{^{'}} + 2 x y = 3 cos^{2} (x)

g (x) = 5 x, at x = 9

\int x^{2} x^{2} - 64 d x

ln (\frac{2}{x})

What is the tangent of y= 1/(x^3),(-3,-1/27) ?
The tangent of y= 1/(x^3),(-3,-1/27) is y=-1/27 x-4/27