What is (\partial)/(\partial x)(e^x*ln(y)) ?

The answer to (\partial)/(\partial x)(e^x*ln(y)) is ln(y)e^x

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(\partial)/(\partial x)(e^x*ln(y))

\frac{\partial}{\partial x} (e^{x} \cdot ln (y))

ln (y) e^{x}

Solution steps

\frac{\partial}{\partial x} (e^{x} ln (y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= ln (y) \frac{\partial}{\partial x} (e^{x})

Apply the common derivative:

\frac{\partial}{\partial x} (e^{x}) = e^{x}

= ln (y) e^{x}

sin (x^{2})

\frac{d}{d x} (\frac{3 x - 4}{x + 2})

\int \frac{1}{3 x - 1} d x

\int_{- 4}^{4} 4 - x^{2} d x

\int (x^{\frac{4}{3}} + 4 x^{\frac{1}{3}}) d x

What is (\partial)/(\partial x)(e^x*ln(y)) ?
The answer to (\partial)/(\partial x)(e^x*ln(y)) is ln(y)e^x