What is (\partial)/(\partial x)(2-y-2x) ?

The answer to (\partial)/(\partial x)(2-y-2x) is -2

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(\partial)/(\partial x)(2-y-2x)

\frac{\partial}{\partial x} (2 - y - 2 x)

- 2

Solution steps

\frac{\partial}{\partial x} (2 - y - 2 x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2) - \frac{\partial}{\partial x} (y) - \frac{\partial}{\partial x} (2 x)

\frac{\partial}{\partial x} (2) = 0

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (2 x) = 2

= 0 - 0 - 2

Simplify

= - 2

\int \frac{( x ^{2} + 2 )}{( x ^{3} + 6 x )} d x

y = x^{2} + 2

\int \frac{2}{x ^{2} + 16} d x

\frac{d}{d x} (\frac{x ^{6} + 2}{8 x ^{2}})

\frac{5 u ^{2}}{( u ^{2} + u ) ^{3}}

What is (\partial)/(\partial x)(2-y-2x) ?
The answer to (\partial)/(\partial x)(2-y-2x) is -2