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Popular >

y^{''}-289y=0

Solution

y^{^{''}} - 289 y = 0

Solution

y = c_{1} e^{17 t} + c_{2} e^{- 17 t}

Solution steps

y^{''} (t) - 289 y = 0

Solve linear ODE:

y = c_{1} e^{17 t} + c_{2} e^{- 17 t}

y = c_{1} e^{17 t} + c_{2} e^{- 17 t}

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Frequently Asked Questions (FAQ)

What is the solution for y^{''}-289y=0 ?
The solution for y^{''}-289y=0 is y=c_{1}e^{17t}+c_{2}e^{-17t}