What is (\partial)/(\partial x)(ycos(x)+sin(x)) ?

The answer to (\partial)/(\partial x)(ycos(x)+sin(x)) is -ysin(x)+cos(x)

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(\partial)/(\partial x)(ycos(x)+sin(x))

\frac{\partial}{\partial x} (y cos (x) + sin (x))

- y sin (x) + cos (x)

Solution steps

\frac{\partial}{\partial x} (y cos (x) + sin (x))

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y cos (x)) + \frac{\partial}{\partial x} (sin (x))

\frac{\partial}{\partial x} (y cos (x)) = - y sin (x)

\frac{\partial}{\partial x} (sin (x)) = cos (x)

= - y sin (x) + cos (x)

\int x^{2} (6 - x^{3})^{5} d x

(- 3) (1.2)

\frac{d}{d x} (\frac{1}{y} + x ln (y))

\int ln (x) \cdot x d x

f (x) = 2 x 3 - 4 x, at x = - 1

What is (\partial)/(\partial x)(ycos(x)+sin(x)) ?
The answer to (\partial)/(\partial x)(ycos(x)+sin(x)) is -ysin(x)+cos(x)