What is taylor 8/(sqrt(x)) ?

The answer to taylor 8/(sqrt(x)) is 8-4(x-1)+3(x-1)^2-5/2 (x-1)^3+35/16 (x-1)^4+\ldots

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taylor 8/(sqrt(x))

taylor

\frac{8}{x}

8 - 4 (x - 1) + 3 (x - 1)^{2} - \frac{5}{2} (x - 1)^{3} + \frac{35}{16} (x - 1)^{4} + \dots

Solution steps

Apply the Taylor Formula

= 8 + \frac{\frac{d}{d x} ( \frac{8}{x} ) ( 1 )}{1 !} (x - 1) + \frac{\frac{d ^{2}}{d x ^{2}} ( \frac{8}{x} ) ( 1 )}{2 !} (x - 1)^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( \frac{8}{x} ) ( 1 )}{3 !} (x - 1)^{3} + \dots

Evaluate Derivatives

= 8 + \frac{- 4}{1 !} (x - 1) + \frac{6}{2 !} (x - 1)^{2} + \frac{- 15}{3 !} (x - 1)^{3} + \frac{\frac{105}{2}}{4 !} (x - 1)^{4} + \dots

Refine

= 8 - 4 (x - 1) + 3 (x - 1)^{2} - \frac{5}{2} (x - 1)^{3} + \frac{35}{16} (x - 1)^{4} + \dots

\int tan (9 x se) c^{2} 9 x d x

\frac{d y}{d x} = \frac{( x - 1 )}{y - 3}

\int \frac{1}{4 - 5 x} d x

\frac{\partial}{\partial x} (x^{3})

\frac{\partial}{\partial x} ((3 x^{2} + 5 x + 1) \cdot (y + 4))

What is taylor 8/(sqrt(x)) ?
The answer to taylor 8/(sqrt(x)) is 8-4(x-1)+3(x-1)^2-5/2 (x-1)^3+35/16 (x-1)^4+\ldots