What is the derivative of x/4-4/x ?

The derivative of x/4-4/x is 1/4+4/(x^2)

What is the first derivative of x/4-4/x ?

The first derivative of x/4-4/x is 1/4+4/(x^2)

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derivative of

\frac{x}{4} - \frac{4}{x}

\frac{1}{4} + \frac{4}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{x}{4} - \frac{4}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x}{4}) - \frac{d}{d x} (\frac{4}{x})

\frac{d}{d x} (\frac{x}{4}) = \frac{1}{4}

\frac{d}{d x} (\frac{4}{x}) = - \frac{4}{x ^{2}}

= \frac{1}{4} - (- \frac{4}{x ^{2}})

Simplify

= \frac{1}{4} + \frac{4}{x ^{2}}

x^{2} \frac{d y}{d x} - 2 x y = 6 y^{4}, y (1) = \frac{1}{3}

x \to \infty lim (7 x)

\int \frac{1}{x + 7} d x

\int_{4}^{5} \frac{x}{8} d x

\int ln (a + b x) d x

What is the derivative of x/4-4/x ?
The derivative of x/4-4/x is 1/4+4/(x^2)
What is the first derivative of x/4-4/x ?
The first derivative of x/4-4/x is 1/4+4/(x^2)