What is the integral from 0 to 5 of 4x^2 ?

The integral from 0 to 5 of 4x^2 is 500/3

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integral from 0 to 5 of 4x^2

\int_{0}^{5} 4 x^{2} d x

\frac{500}{3}

Decimal

166.66666 \dots

Solution steps

\int_{0}^{5} 4 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{0}^{5} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{5}

= 4 [\frac{x ^{3}}{3}]_{0}^{5}

Compute the boundaries:

\frac{125}{3}

= 4 \cdot \frac{125}{3}

Simplify

= \frac{500}{3}

\int 2 z^{2} d z

\int \frac{1}{3 - 6 x - x ^{2}} d x

x \to 0 lim (5 x + 4)

\frac{\partial}{\partial x} (ln (5 x^{2} + 4 y^{2} + 7))

\frac{\partial}{\partial x} (2 x^{2} + 2 y^{2})

What is the integral from 0 to 5 of 4x^2 ?
The integral from 0 to 5 of 4x^2 is 500/3