What is the tangent of f(x)= 1/x ,(a, 1/a) ?

The tangent of f(x)= 1/x ,(a, 1/a) is y=-1/(a^2)x+2/a

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tangent of f(x)= 1/x ,(a, 1/a)

tangent of

f (x) = \frac{1}{x}, (a, \frac{1}{a})

y = - \frac{1}{a ^{2}} x + \frac{2}{a}

Solution steps

Find the slope of

f (x) = \frac{1}{x} : \frac{df ( x )}{d x} = - \frac{1}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{a ^{2}}

Find the line with slope m=

- \frac{1}{a ^{2}}

and passing through

(a, \frac{1}{a}) : y = - \frac{1}{a ^{2}} x + \frac{2}{a}

y = - \frac{1}{a ^{2}} x + \frac{2}{a}

3 x (x^{3} - 7 x + 4)

\int_{1}^{4} \frac{1}{x - 2} d x

\frac{d}{d x} f (x) = 10 x^{2} tan (x)

\int \frac{x}{3 - x ^{2}} d x

y^{^{'}} + (2 sin (x) cos (x)) y = e^{- s i n^{2} (x)}

What is the tangent of f(x)= 1/x ,(a, 1/a) ?
The tangent of f(x)= 1/x ,(a, 1/a) is y=-1/(a^2)x+2/a