What is the derivative of 6e^{x^2}x ?

The derivative of 6e^{x^2}x is 6(2e^{x^2}x^2+e^{x^2})

What is the first derivative of 6e^{x^2}x ?

The first derivative of 6e^{x^2}x is 6(2e^{x^2}x^2+e^{x^2})

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\frac{d}{d x} (6 e^{x^{2}} x)

6 (2 e^{x^{2}} x^{2} + e^{x^{2}})

Solution steps

\frac{d}{d x} (6 e^{x^{2}} x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (e^{x^{2}} x)

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = e^{x^{2}}, g = x

= 6 (\frac{d}{d x} (e^{x^{2}}) x + \frac{d x}{d x} e^{x^{2}})

\frac{d}{d x} (e^{x^{2}}) = e^{x^{2}} \cdot 2 x

\frac{d x}{d x} = 1

= 6 (e^{x^{2}} \cdot 2 xx + 1 \cdot e^{x^{2}})

Simplify

6 (e^{x^{2}} \cdot 2 xx + 1 \cdot e^{x^{2}}) : 6 (2 e^{x^{2}} x^{2} + e^{x^{2}})

= 6 (2 e^{x^{2}} x^{2} + e^{x^{2}})

y^{^{'}} = y^{2} sin (x)

\int_{1}^{4} \frac{1}{x + 2 x} d x

\frac{d}{d x} (\frac{e ^{- x}}{2})

\frac{d}{d y} (x^{2} + y^{2} - 5)

g (w) = \frac{9}{8 w ^{5}} + 9 w

What is the derivative of 6e^{x^2}x ?
The derivative of 6e^{x^2}x is 6(2e^{x^2}x^2+e^{x^2})
What is the first derivative of 6e^{x^2}x ?
The first derivative of 6e^{x^2}x is 6(2e^{x^2}x^2+e^{x^2})