What is (\partial)/(\partial x)(1-2x^2-2y) ?

The answer to (\partial)/(\partial x)(1-2x^2-2y) is -4x

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(\partial)/(\partial x)(1-2x^2-2y)

\frac{\partial}{\partial x} (1 - 2 x^{2} - 2 y)

- 4 x

Solution steps

\frac{\partial}{\partial x} (1 - 2 x^{2} - 2 y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (1) - \frac{\partial}{\partial x} (2 x^{2}) - \frac{\partial}{\partial x} (2 y)

\frac{\partial}{\partial x} (1) = 0

\frac{\partial}{\partial x} (2 x^{2}) = 4 x

\frac{\partial}{\partial x} (2 y) = 0

= 0 - 4 x - 0

Simplify

= - 4 x

(1 - t^{2}) y^{^{''}} - 2 t y^{^{'}} + 2 y = 0

\frac{d}{d x} ((x + a) e^{2 x})

\int_{0}^{4} x e^{x} d x

\frac{d}{d t} (\frac{t ^{3}}{6} + \frac{t ^{2}}{4} + \frac{1}{2} t)

\int \frac{sec ( x ) tan ( x )}{sec ( x ) - 7} d x

What is (\partial)/(\partial x)(1-2x^2-2y) ?
The answer to (\partial)/(\partial x)(1-2x^2-2y) is -4x