What is (\partial)/(\partial x)(4x^{-1/8}) ?

The answer to (\partial)/(\partial x)(4x^{-1/8}) is -1/(2x^{9/8)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(4x^{-1/8})

\frac{\partial}{\partial x} (4 x^{- \frac{1}{8}})

- \frac{1}{2 x ^{\frac{9}{8}}}

Solution steps

\frac{\partial}{\partial x} (4 x^{- \frac{1}{8}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{\partial}{\partial x} (x^{- \frac{1}{8}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 (- \frac{1}{8} x^{- \frac{1}{8} - 1})

Simplify

4 (- \frac{1}{8} x^{- \frac{1}{8} - 1}) : - \frac{1}{2 x ^{\frac{9}{8}}}

= - \frac{1}{2 x ^{\frac{9}{8}}}

\int 3 x^{2} e^{- 3 x} d x

\frac{d}{d x} (6 x^{2} (4 x^{5} - 3 x + 2))

x \to 0 + lim (x^{3} (ln (x))^{2})

y = x (1 + x^{2})^{10}

x \to 0 - lim (\frac{x}{x})

What is (\partial)/(\partial x)(4x^{-1/8}) ?
The answer to (\partial)/(\partial x)(4x^{-1/8}) is -1/(2x^{9/8)}