What is the derivative of arccos(-3x) ?

The derivative of arccos(-3x) is 3/(sqrt(1-9x^2))

What is the first derivative of arccos(-3x) ?

The first derivative of arccos(-3x) is 3/(sqrt(1-9x^2))

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\frac{d}{d x} (arccos (- 3 x))

\frac{3}{1 - 9 x ^{2}}

Solution steps

\frac{d}{d x} (arccos (- 3 x))

Apply the chain rule:

- \frac{1}{1 - ( - 3 x ) ^{2}} \frac{d}{d x} (- 3 x)

= - \frac{1}{1 - ( - 3 x ) ^{2}} \frac{d}{d x} (- 3 x)

\frac{d}{d x} (- 3 x) = - 3

= - \frac{1}{1 - ( - 3 x ) ^{2}} (- 3)

Simplify

- \frac{1}{1 - ( - 3 x ) ^{2}} (- 3) : \frac{3}{1 - 9 x ^{2}}

= \frac{3}{1 - 9 x ^{2}}

y^{^{''}} + 16 = 0

\frac{d}{d x} \frac{( e ^{- x^{2}} )}{x ^{3}}

\int \frac{x}{4} d x

x \to 8 lim (\frac{∣ x - 8 ∣}{x - 8})

x \to 6 + lim (\frac{2 + x}{6 - x})

What is the derivative of arccos(-3x) ?
The derivative of arccos(-3x) is 3/(sqrt(1-9x^2))
What is the first derivative of arccos(-3x) ?
The first derivative of arccos(-3x) is 3/(sqrt(1-9x^2))