What is the first derivative of-kx ?

The first derivative of-kx is -k

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derivative of-kx

\frac{d}{d x} (- k x)

- k

Solution steps

\frac{d}{d x} (- k x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - k \frac{d x}{d x}

Apply the common derivative:

\frac{d x}{d x} = 1

= - k \cdot 1

Simplify

= - k

\int cos (x) - x sin (x) d x

e^{- x^{62}}

y^{^{'}} = x - 2 y

(1, 4), (- 5, 2)

\int \frac{1}{12 x - 9 x ^{2} - 2} d x