What is the solution for y^'=(6x^6e^{y/x}+x^4y^2)/(x^5y) ?

The solution for y^'=(6x^6e^{y/x}+x^4y^2)/(x^5y) is y=-\W((6ln(x)+c_{1})/e)x-x

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y^'=(6x^6e^{y/x}+x^4y^2)/(x^5y)

y^{^{'}} = \frac{6 x ^{6} e ^{\frac{y}{x}} + x ^{4} y ^{2}}{x ^{5} y}

y = - W (\frac{6 ln ( x ) + c _{1}}{e}) x - x

Solution steps

y^{'} (x) = \frac{6 x ^{6} e ^{\frac{y}{x}} + x ^{4} y ^{2}}{x ^{5} y}

Solve using substitution:

y = - W (\frac{6 ln ( x ) + c _{1}}{e}) x - x

y = - W (\frac{6 ln ( x ) + c _{1}}{e}) x - x

\int (x^{2} - 7 x + 5) d x

\frac{d}{d x} (\frac{4 - 2 x - x ^{3}}{3 x - x ^{4}})

y = 0, y = 9 - x^{2}, y = 0

f (x) = \frac{1}{x ^{4}}, (3, \frac{1}{81})

\int \frac{\frac{4}{x ^{3}} + 2}{\frac{1}{x ^{2}} - x} d x

What is the solution for y^'=(6x^6e^{y/x}+x^4y^2)/(x^5y) ?
The solution for y^'=(6x^6e^{y/x}+x^4y^2)/(x^5y) is y=-\W((6ln(x)+c_{1})/e)x-x