What is the tangent of x-2x^2 ?

The tangent of x-2x^2 is y=(1-4a_{0})x+2a_{0}^2

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tangent of x-2x^2

tangent of

x - 2 x^{2}

y = (1 - 4 a_{0}) x + 2 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0} - 2 a_{0}^{2})

Find the slope of

y = x - 2 x^{2} : \frac{d y}{d x} = 1 - 4 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 1 - 4 a_{0}

Find the line with slope m=

1 - 4 a_{0}

and passing through

(a_{0}, a_{0} - 2 a_{0}^{2}) : y = (1 - 4 a_{0}) x + 2 a_{0}^{2}

y = (1 - 4 a_{0}) x + 2 a_{0}^{2}

\frac{d ^{3}}{d x ^{3}} (e^{5 x - 4})

n = 1 \sum \infty \frac{n !}{9 0 ^{n}}

x \to 2 lim (2 x^{3} - x^{2} + 7 x - 3)

\frac{d}{d x} (2 tan (x) sec (x))

\frac{d}{d x} (- 3 x)