What is (\partial)/(\partial x)(sin(pi(x-2y))) ?

The answer to (\partial)/(\partial x)(sin(pi(x-2y))) is cos(pi(x-2y))pi

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(\partial)/(\partial x)(sin(pi(x-2y)))

\frac{\partial}{\partial x} (sin (π (x - 2 y)))

cos (π (x - 2 y)) π

Solution steps

\frac{\partial}{\partial x} (sin (π (x - 2 y)))

Treat

y

as a constant

Apply the chain rule:

cos (π (x - 2 y)) \frac{\partial}{\partial x} (π (x - 2 y))

= cos (π (x - 2 y)) \frac{\partial}{\partial x} (π (x - 2 y))

\frac{\partial}{\partial x} (π (x - 2 y)) = π

= cos (π (x - 2 y)) π

\frac{d}{d x} (e^{- x} - ln (x))

y^{^{'}} = e^{3 x - 7 y}

\frac{d}{d x} (\frac{e ^{x} + e ^{- x}}{9})

x^{\frac{2}{3}} + y^{\frac{2}{3}} = 4

\int (x^{2} + x) d x

What is (\partial)/(\partial x)(sin(pi(x-2y))) ?
The answer to (\partial)/(\partial x)(sin(pi(x-2y))) is cos(pi(x-2y))pi