What is (\partial)/(\partial x)(ln(y-x)) ?

The answer to (\partial)/(\partial x)(ln(y-x)) is -1/(y-x)

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(\partial)/(\partial x)(ln(y-x))

\frac{\partial}{\partial x} (ln (y - x))

- \frac{1}{y - x}

Solution steps

\frac{\partial}{\partial x} (ln (y - x))

Treat

y

as a constant

Apply the chain rule:

\frac{1}{y - x} \frac{\partial}{\partial x} (y - x)

= \frac{1}{y - x} \frac{\partial}{\partial x} (y - x)

\frac{\partial}{\partial x} (y - x) = - 1

= \frac{1}{y - x} (- 1)

Simplify

= - \frac{1}{y - x}

\frac{d}{d x} (\frac{x ^{6}}{2 - x ^{5}})

\frac{d}{d x} ((2.5)^{x})

y = 4 x e^{- k x}

\int \frac{64 - x ^{2}}{x} d x

f (x) = 2 x^{2} - 3 x, at x = 2

What is (\partial)/(\partial x)(ln(y-x)) ?
The answer to (\partial)/(\partial x)(ln(y-x)) is -1/(y-x)