What is the sum from n=8 to infinity of (7/8)^{-n} ?

The sum from n=8 to infinity of (7/8)^{-n} is diverges

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sum from n=8 to infinity of (7/8)^{-n}

n = 8 \sum \infty (\frac{7}{8})^{- n}

diverges

Solution steps

n = 8 \sum \infty (\frac{7}{8})^{- n}

Apply Series Ratio Test:

diverges

= diverges

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x \to 2 + lim (in t x)

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What is the sum from n=8 to infinity of (7/8)^{-n} ?
The sum from n=8 to infinity of (7/8)^{-n} is diverges