What is the solution for 2xy^2+x^2(dy)/(dx)=y^2 ?

The solution for 2xy^2+x^2(dy)/(dx)=y^2 is y=-x/(-1+2x-2xln(x)+c_{1)x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2xy^2+x^2(dy)/(dx)=y^2

2 x y^{2} + x^{2} \frac{d y}{d x} = y^{2}

y = - \frac{x}{- 1 + 2 x - 2 x ln ( x ) + c _{1} x}

Solution steps

2 x y^{2} + x^{2} \frac{d y}{d x} = y^{2}

Solve separable ODE:

y = - \frac{x}{- 1 + 2 x - 2 x ln ( x ) + c _{1} x}

y = - \frac{x}{- 1 + 2 x - 2 x ln ( x ) + c _{1} x}

\int e^{- θ} cos (3 θ) d θ

\int \frac{x ^{2}}{( x - 1 ) ( x ^{2} - 1 )} d x

\frac{\partial}{\partial z} (x^{2} + y^{2} - z)

\int sin (x) sin (6 x) d x

\frac{1}{3 x ^{\frac{2}{3}}}

What is the solution for 2xy^2+x^2(dy)/(dx)=y^2 ?
The solution for 2xy^2+x^2(dy)/(dx)=y^2 is y=-x/(-1+2x-2xln(x)+c_{1)x}