What is the integral from-32 to 8 of 1/(sqrt(|2x|)) ?

The integral from-32 to 8 of 1/(sqrt(|2x|)) is 12

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integral from-32 to 8 of 1/(sqrt(|2x|))

\int_{- 32}^{8} \frac{1}{∣ 2 x ∣} d x

12

Solution steps

\int_{- 32}^{8} \frac{1}{∣ 2 x ∣} d x

Eliminate Absolutes

= \int_{- 32}^{0} \frac{1}{- 2 x} d x + \int_{0}^{8} \frac{1}{2 x} d x

\int_{- 32}^{0} \frac{1}{- 2 x} d x = 8

\int_{0}^{8} \frac{1}{2 x} d x = 4

= 8 + 4

Simplify

= 12

63 cos (7 x)

\frac{1}{4} x^{2} - 1, y = 8, y = 2

\int_{0}^{π} 2 sin^{4} (3 t) d t

y^{^{''}} - 5 y^{^{'}} + 4 y = 0, y (0) = 1, y^{^{'}} (0) = \frac{1}{4}

n = 4 \sum \infty 3 - 0. 5^{n}

What is the integral from-32 to 8 of 1/(sqrt(|2x|)) ?
The integral from-32 to 8 of 1/(sqrt(|2x|)) is 12