What is the derivative of 4x^3-6x ?

The derivative of 4x^3-6x is 12x^2-6

What is the first derivative of 4x^3-6x ?

The first derivative of 4x^3-6x is 12x^2-6

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\frac{d}{d x} (4 x^{3} - 6 x)

12 x^{2} - 6

Solution steps

\frac{d}{d x} (4 x^{3} - 6 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) - \frac{d}{d x} (6 x)

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (6 x) = 6

= 12 x^{2} - 6

3 - e^{2 t}

f (x) = 2 - x

f (x) = \frac{5 x + 1}{x - 1}

y = x^{2} - 4, y = 8 - 2 x^{2}

\frac{\partial}{\partial y} (- 3 e^{x} cos (yz))

What is the derivative of 4x^3-6x ?
The derivative of 4x^3-6x is 12x^2-6
What is the first derivative of 4x^3-6x ?
The first derivative of 4x^3-6x is 12x^2-6