What is (\partial)/(\partial r)(r^{2+s^2}) ?

The answer to (\partial)/(\partial r)(r^{2+s^2}) is r^{s^2+1}(2+s^2)

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(\partial)/(\partial r)(r^{2+s^2})

\frac{\partial}{\partial r} (r^{2 + s^{2}})

r^{s^{2} + 1} (2 + s^{2})

Solution steps

\frac{\partial}{\partial r} (r^{2 + s^{2}})

Treat

s

as a constant

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= (2 + s^{2}) r^{2 + s^{2} - 1}

Simplify

= r^{s^{2} + 1} (2 + s^{2})

\frac{t}{t ^{2} + 1}

y^{^{''}} + 15 y^{^{'}} + 56 y = 0

\frac{d y}{d x} + 9 y = 5

t^{2} y^{^{'}} + y^{2} = t y

(3 x^{2} + x) (5 x^{3} + 1)

What is (\partial)/(\partial r)(r^{2+s^2}) ?
The answer to (\partial)/(\partial r)(r^{2+s^2}) is r^{s^2+1}(2+s^2)