What is the integral of sin(x)(1-cos(x)) ?

The integral of sin(x)(1-cos(x)) is ((1-cos(x))^2)/2+C

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integral of sin(x)(1-cos(x))

\int sin (x) (1 - cos (x)) d x

\frac{( 1 - cos ( x ) ) ^{2}}{2} + C

Solution steps

\int sin (x) (1 - cos (x)) d x

Apply u-substitution

: \int u d u

= \int u d u

Apply the Power Rule

: \frac{u ^{2}}{2}

= \frac{u ^{2}}{2}

Substitute back

u = 1 - cos (x)

= \frac{( 1 - cos ( x ) ) ^{2}}{2}

Add a constant to the solution

= \frac{( 1 - cos ( x ) ) ^{2}}{2} + C

\frac{d}{d x} (\frac{x ^{2} - 6 x}{1 + cos ( x )})

\int \frac{1}{x ^{2} + 4 x + 25} d x

\int x 4 - x d x

\int_{0}^{1} 2 y^{2} d y

ln (e^{- x} + x e^{- x})

What is the integral of sin(x)(1-cos(x)) ?
The integral of sin(x)(1-cos(x)) is ((1-cos(x))^2)/2+C