What is the solution for (dy)/(dx)=(2y)/(x+1) ?

The solution for (dy)/(dx)=(2y)/(x+1) is y=e^{c_{1}}x^2+2e^{c_{1}}x+e^{c_{1}}

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(dy)/(dx)=(2y)/(x+1)

\frac{d y}{d x} = \frac{2 y}{x + 1}

y = e^{c_{1}} x^{2} + 2 e^{c_{1}} x + e^{c_{1}}

Solution steps

\frac{d y}{d x} = \frac{2 y}{x + 1}

Solve separable ODE:

y = e^{c_{1}} x^{2} + 2 e^{c_{1}} x + e^{c_{1}}

y = e^{c_{1}} x^{2} + 2 e^{c_{1}} x + e^{c_{1}}

x \to 1 lim (x + 4)

n = 1 \sum \infty \frac{n}{( 5 ^{n} )}

\int x^{2} \cdot sin (2 x) d x

\frac{d}{d x} ((4 x^{2} + 1)^{- 50})

\int (\frac{x ^{2} + 3 x - 5}{x - 3}) d x

What is the solution for (dy)/(dx)=(2y)/(x+1) ?
The solution for (dy)/(dx)=(2y)/(x+1) is y=e^{c_{1}}x^2+2e^{c_{1}}x+e^{c_{1}}