What is the derivative of tan(3x-4y) ?

The derivative of tan(3x-4y) is sec^2(3x-4y)(3-4(dy)/(dx))

What is the first derivative of tan(3x-4y) ?

The first derivative of tan(3x-4y) is sec^2(3x-4y)(3-4(dy)/(dx))

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\frac{d}{d x} (tan (3 x - 4 y))

sec^{2} (3 x - 4 y) (3 - 4 \frac{d y}{d x})

Solution steps

\frac{d}{d x} (tan (3 x - 4 y))

Apply the chain rule:

sec^{2} (3 x - 4 y) \frac{d}{d x} (3 x - 4 y)

= sec^{2} (3 x - 4 y) \frac{d}{d x} (3 x - 4 y)

\frac{d}{d x} (3 x - 4 y) = 3 - 4 \frac{d y}{d x}

= sec^{2} (3 x - 4 y) (3 - 4 \frac{d y}{d x})

\frac{d y}{d x} + 2 x y = \frac{x}{y ^{2}}

\frac{d}{d x} ((csc (x))^{- 1})

\int_{0}^{2} 2 π x (2 x - x^{2}) d x

\int cot (18 x) d x

\frac{d}{d x} (x^{2} + 10 x)

What is the derivative of tan(3x-4y) ?
The derivative of tan(3x-4y) is sec^2(3x-4y)(3-4(dy)/(dx))
What is the first derivative of tan(3x-4y) ?
The first derivative of tan(3x-4y) is sec^2(3x-4y)(3-4(dy)/(dx))