What is the derivative of 5sin(4x) ?

The derivative of 5sin(4x) is 20cos(4x)

What is the first derivative of 5sin(4x) ?

The first derivative of 5sin(4x) is 20cos(4x)

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\frac{d}{d x} (5 sin (4 x))

20 cos (4 x)

Solution steps

\frac{d}{d x} (5 sin (4 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (sin (4 x))

Apply the chain rule:

cos (4 x) \frac{d}{d x} (4 x)

= cos (4 x) \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = 4

= 5 cos (4 x) \cdot 4

Simplify

= 20 cos (4 x)

(2 x)^{x}

\int \frac{2}{16 + 3 x ^{2}} d x

re g a r d s p \frac{I}{2 p}

\int \frac{1}{4 ( 1 - x ) ^{2}} d x

\frac{d ^{2} y}{d x ^{2}} = 4 x

What is the derivative of 5sin(4x) ?
The derivative of 5sin(4x) is 20cos(4x)
What is the first derivative of 5sin(4x) ?
The first derivative of 5sin(4x) is 20cos(4x)