What is the integral of (2x+5)/(x^2) ?

The integral of (2x+5)/(x^2) is 2ln|x|-5/x+C

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integral of (2x+5)/(x^2)

\int \frac{2 x + 5}{x ^{2}} d x

2 ln ∣ x ∣ - \frac{5}{x} + C

Solution steps

\int \frac{2 x + 5}{x ^{2}} d x

Expand

\frac{2 x + 5}{x ^{2}} : \frac{2}{x} + \frac{5}{x ^{2}}

= \int \frac{2}{x} + \frac{5}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{2}{x} d x + \int \frac{5}{x ^{2}} d x

\int \frac{2}{x} d x = 2 ln ∣ x ∣

\int \frac{5}{x ^{2}} d x = - \frac{5}{x}

= 2 ln ∣ x ∣ - \frac{5}{x}

Add a constant to the solution

= 2 ln ∣ x ∣ - \frac{5}{x} + C

\int \frac{1}{( x ^{2} + 4 x + 5 )} d x

\frac{d}{d x} (4 - \frac{600}{x ^{2}})

y = 2 x^{2}, (- 1, 2)

\frac{\partial}{\partial x} (- 2 e^{x})

\frac{d}{d x} (- \frac{2 x ^{2}}{5 y ^{2}})

What is the integral of (2x+5)/(x^2) ?
The integral of (2x+5)/(x^2) is 2ln|x|-5/x+C